Question

1 mole of propane (C3 H8) on combustion at STP gives A kilo joules of heat energy. calculate the heat liberated when 2.4 litrs of propane on combustion at STP.

Answer 1

Answer:

At STP combustion is done by 1 mole of O2 i.e 22.4 lit,gave 1000kj of heat

given,

2.4lit

Energy liberated is 1/10 if the energy liberated at STP through ratio

i.e

22.4lit->1000kj

2.4lit->x kj

x=1000×2.4/22.4

=1000×0.107

=107kj

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