Question

1 mole of real gas (a=1.4)occupies a volume of 0.1L at 300K then the pressure of gas will be
(1)2460 atm
(2)2320 atm
(3)106 atm
(4)425 atm​

Answer 1

n=1

a=1.4

v=0.1 lt

T=300k

P =nrt/v-a ×n square/ v square

=1×0.082×300/o.1-1.4×1 square /0.1 square

=246-140

=106 atm

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