Question

1 mole of real gas (a = 1.4) oocupies a volume of
0.1L at 300K then the pressure of gas will be
(1) 2460 atm
(2) 2320 atrn
(3) 106 atm
(4) 212 atm​

Answer 1

Dear Student,

◆ Answer - (3)

P = 106 atm

◆ Explanation -

# Given -

n = 1

a = 1.4

V = 0.1 L

T = 300 K

# Solution -

Pressure of real gas is given by -

P = nRT/V - an²/V²

Substitute values

P = 1 × 0.082 × 300 / 0.1 - 1.4 × 1² / 0.1²

P = 246 - 140

P = 106 atm

Therefore, atmospheric pressure of the gas will be 106 atm.

Hope that's all...

Answer 2

Answer:

(P+a/v*2 ) v =nrt

By putting the value as given in question

P=106 atm

Thank u