Question

1 mole of water at 1 atm and 100 c evaporates to 1 mole water vapour. calculate the entropy change

Answer 1

Answer:

Heat of vapourisation at 100

0

C=540 Cal/gm

Molar heat of vapourisation =540×18 Cal/gm

ΔS=

T

q

rev

=

373

540×18

ΔS=26.06 Cal/gm

Answer 2

Explanation:

Heat of vapourisation at 100 °C=540 Cal/gm

Molar heat of vapourisation =540×18 Cal/gm

ΔS=   q  rev  / T

​  ​  

=  540×18  / 373

​  

ΔS=26.06 Cal/gm