Question

1.Mr Budhi bought a house for 65,43,200. He spent 35,46,300
in repairing it. If he then sold the house for 99,99,900, did he
lose or gain money? How much?
2. ABC Public School bought 2 buses and a car for 20,55,300.
If the cost of a bus is 8,45,560, find the cost of the car.​

Answer 1

Step-by-step explanation:

$the \: abve \: amswer \: is \: correct$

Answer 2

Answer:

\begin{gathered}\frak {Given} \begin{cases} & \sf{H.C.F\:of\:two\:numbers = \bf{9}} \\ & \sf{L.C.M\:of\:two\:numbers = \bf{90}} \\ & \sf{One\:of\:the\;number\:is = \bf{18}} \end{cases}\\ \\\end{gathered}

Given

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H.C.Foftwonumbers=9

L.C.Moftwonumbers=90

Oneofthenumberis=18

To find: Other number?⠀⠀⠀⠀━━━━━━━━━━━━━━━━━━━━━⠀

☯ Let's consider the other number be x.

\begin{gathered}\dag\;{\underline{\frak{As\;we\;know\;that,}}}\\ \\\end{gathered}

†

Asweknowthat,

\begin{gathered}\star\;{\boxed{\sf{\pink{L.C.M \times H.C.F = a \times b}}}}\\ \\\end{gathered}

⋆

L.C.M×H.C.F=a×b

where, a and b are two numbers.⠀⠀

⠀⠀\begin{gathered}\dag\;{\underline{\frak{Now,\: Substituting\:values\:in\:formula,}}}\\ \\\end{gathered}

†

Now,Substitutingvaluesinformula,

\begin{gathered}:\implies\sf 90 \times 9 = 18 \times x \\\\\\:\implies\sf x = 9 \times \dfrac{\cancel{90}}{\cancel{18}} \\\\\\:\implies\sf x = 9 \times 5\\\\\\:\implies\boxed{\frak{\purple{x = 45}}}\end{gathered}

:⟹90×9=18×x

:⟹x=9×

18

90

:⟹x=9×5

:⟹

x=45

\therefore\:{\underline{\sf{The\:other\:number\:is\: {\textsf{\textbf{45}}}.}}}∴

Theothernumberis45.

⠀⠀⠀⠀━━━━━━━━━━━━━━━━━━━━━⠀⠀

\begin{gathered}\qquad\qquad\boxed{\underline{\underline{\pink{\bigstar \: \bf\: Additional \ Information \:\bigstar}}}}\\ \\\end{gathered}

★Additional Information★

HCF is the Highest common factor, the number which is present greatest number b/w two, three numbers.

LCM is the Lowest common factor, the least divisible number.