Question

1. On increasing the price of an item by 20%, it becomes *9600. What was its original price?

​

Answer 1

Answer:

Consider the original price of an article = Rs x

9600=(1+20/100) of original price

It can be written as

9600=[(100+20)/100]× Rs x

By further calculation

9600=120/100×x

So we get

120×/100=9600

By separating the terms

x=(9600×100)/120

x=(800×100)

By division

x=800×100

x=80000

Therefore, the original price of an article is Rs 80000.

Answer 2

Increases percentage = 16%

assume original price is X

increased price is 16% of X

9600 = X +(20/100×X)

9600= X + 20X × 100

9600 = 100X /100 + 20X/100

9600 × 120 / 100 =X

11,520 = X .........