Question

1.\overline321=[tex]\frac{4a}{3b}​

Answer 1

$1.\overline{321}=\frac{4a}{3b} \\ \\ 1 +\frac{321}{999} = \frac{4a}{3b} \\ \\ \frac{999 + 321}{999} = \frac{4a}{3b} \\ \\ \frac{1320}{999} = \frac{4}{3} \times \frac{a}{b} \\ \\ \frac{a}{b} = \frac{1320}{999} \times \frac{3}{4} \\ \\ \frac{a}{b} = \frac{330}{333} \\ \\ \frac{a}{b} = \bold{ \frac{110}{111}} \\ \\ \frac{a}{b} = \frac{990}{999} \\ \\ \frac{a}{b} = 0. \overline{990}$

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Answer 2

0.990Answer.............

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