1. Oxidation states of P in H4p2o5 h4p2o6. h4p2o7 are
respectively
[AIPMT (Prelims)-2010]
(1) +3, +5, +4 (2) +5, +3, +4
(3) +5, +4, +3 (4) +3, +4, +5
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Answer:
Correct option (d) +3, +4, +5
EXPLAINATION:
(+1)4+2X+(-2)5=0;X=+2
(+1)4+2X+(-2)5=0;X=+2(+1)4+2X+(-2)6=0;X=+4
(+1)4+2X+(-2)5=0;X=+2(+1)4+2X+(-2)6=0;X=+4(+1)4+2X+(-2)7=0;X=+5
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