Math, asked by nishant14337, 8 months ago

1.P(n, 1) +2.P(n, 2) +3.P(n, 3) +...... +n.P(n, n) = *
P(n+1.n+1) -1
P(n+1, n+1)
P(n+2, n+2)
None of these​

Answers

Answered by Dharshini1359
1

Answer:

P(n+1.n+1) -1

Step-by-step explanation:

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