Math, asked by Aaditdesai26, 12 hours ago

1) Perimeter of a square is 20 cm, then what will be the area of that square​

Answers

Answered by Eutuxia
17

Answer :

  • 25 cm²

Given :

  • The perimeter of Square = 20 cm

To find :

  • the area of that square​

Solution :

⇒ Let's first, find the side of the square.

\rightarrow \sf Perimeter \:  of \: Square = 4 \times s

\rightarrow \sf 20 = 4 \times s

\rightarrow \sf s = \dfrac{20}{4}

\rightarrow \sf s = \cancel{\dfrac{20}{4} }

\rightarrow \sf s = 5 cm

⇒ Now, since we have found the side of the square. We can find the Area of the square easily.

\rightarrow \sf Area \:  of \: Square = s^{2}

\sf = 5^{2}

\sf = 5  \times 5

\sf = 25 cm^2

  • Therefore, the Area of the square is 25 cm².

Answered by TheAestheticBoy
9

Question :-

  • If Perimeter of square is 20 cm , then calculate the Area of the Square .

Answer :-

  • Area of Square is 25 cm² .

 \rule {195pt}{2pt}

Given :-

  • Perimeter of Square = 20 cm

To Find :-

  • Area of Square = ?

Solution :-

As per the provided information in the given question, we have been given that Perimeter of Square is 20 cm . And, we have been asked to calculate the Area of Square .

For calculating the Area of Square , first we need to find Side of Square .

Formula Required :-

 \bigstar \:  \:  \boxed{ \sf \pink{ \: Perimeter \:  =  \: 4 \:  \times  \: Side \: }}

Therefore, by Substituting the given values in the above Formula :-

 \longmapsto \:  \:  \sf{20 \:  =  \: 4 \:  \times  \: Side}

 \longmapsto \:  \:  \sf{Side \:  =  \:  \dfrac{20}{4} }

 \longmapsto \:  \:  \textbf {\textsf{Side \:  = \: 5 \: cm}}

Here, we get the value of Side . Now, for calculating the Area of Square :-

Formula Required :-

\bigstar \:  \:  \boxed{ \sf \pink{ \: Area \: of \: Square \:  =  \: ( \: side \: ) \: ^{2} \:  }}

Therefore, by Substituting the given values in the above Formula :-

\longmapsto \:  \:  \sf{Area \: of \: Square \:  =  \: ( \: 5 \: ) \: ^{2} }

\longmapsto \:  \:  \sf{Area \: of \: Square \:  =  \: 5 \: \times \: 5 }

\longmapsto \:  \:  \textbf {\textsf{Area \: of \: Square \:  =  \: 25 \: cm}}

Hence :-

  • Area of Square = 25 cm² .

 \rule {195pt}{4pt}

 \begin{gathered} \begin{gathered} \begin{gathered}\begin{gathered}\boxed{\begin{array}{c} \\ \underline{ { \textbf {\textsf \red{ \dag \: \: More \: Formulas \: \: \dag}}}} \\ \\ \\ \footnotesize \bigstar \: \bf{Area \: _{Square} = Side \times Side} \\ \\ \\ \footnotesize\bigstar \: \bf{Area \: _{Rectangle} = Lenght \times Breadth} \\ \\ \\ \footnotesize \bigstar \: \bf{Area \: _{Triangle} = \dfrac{1}{2} \times Base \times Height } \\ \\ \\ \footnotesize \bigstar \: \bf{Area \: _{Parallelogram} = Base \times Height} \\ \\ \\ \footnotesize \bigstar \: \bf{Area \: _{Trapezium} = \dfrac{1}{2} \times [ \: A + B \: ] \times Height } \\ \\ \\ \footnotesize \bigstar \: \bf {Area \: _{Rhombus} = \dfrac{1}{2} \times Diagonal \: 1 \times Diagonal \: 2}\end{array}}\end{gathered}\end{gathered} \end{gathered} \end{gathered}

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