1 pipe can fill a cistern in 3 hours less than the other . the 2 pipes together can fill the cistern in 6 hours 40 minutes. find the time that each pipe will take to fill the cistern
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time taken by 1st pipe be x
time taken by 2nd pipe be y
given y=x-3hrs= x-180min.
if they together will fill it then they willdo half of their work.
x+y/2= 6h+40m=400min.
x+x-180/2=400min.
x-90=400
x=490min.
x=8hrs and 10min.
y= x-3hrs= 8hrs 10min.-3hrs.
y= 5hrs 10min.
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time taken by 2nd pipe be y
given y=x-3hrs= x-180min.
if they together will fill it then they willdo half of their work.
x+y/2= 6h+40m=400min.
x+x-180/2=400min.
x-90=400
x=490min.
x=8hrs and 10min.
y= x-3hrs= 8hrs 10min.-3hrs.
y= 5hrs 10min.
Please mark as brainliest answer......and press thank you
vasistsanjana:
but the answer is 12 hrs and 15 hrs
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0
time taken by both of them =6hr40min
average time takenby each =6hr40min*2
=400min *2=800min
3hr=180min
so time takenby by first person =800-90=710min=11hr50min
timen taken by second person =800+90min=890min=14hr50min
if helps pls mar it best
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