Question

(1) pls solve this to us a trigo sum​

Answer 1

$\sqrt{1 + {x}^{2} } \sin(y) = x \\ \sin(y) = \frac{x}{ \sqrt{1 + {x}^{2} } } \\ {sin}^{2}y = \frac{ {x}^{2} }{1 + {x}^{2} } \\ {cos}^{2} y = 1 - sin {}^{2} y = \frac{1}{1 + {x}^{2} } \\ \\ {tan}^{2} y + {cot}^{2} y = \frac{sin {}^{2}y + cos { }^{2}y }{ {sin}^{2} y {cos}^{2}y }$

HOPE THIS HELPS PLZ MARK AS BRAINLIEST.