Question

1 po
2.
The factorisation of x2 + xy + 2x +
2y is
(x + 2)(x + y)
(x - 2)(x + y)
(x-2)(x - y).
(x + 2)(x - y)
Time remaining. 00:46​

Answer 1

Answer:

6x2y2z = 2 × 3 × x × x × y × y × z. The common factors are x, x, y, y. And. x × x × y ×y. 2. ... 2x + 1). = 4(x2 – 2 × x × 1 + 12). = 4 (x – 1)2. [Using: a2 – 2ab + b2 = (a – b)2]. = 4(x – 1)(x – 1). · या

Answer 2

Answer:

Factor x 2 + xy - 2x - 2y. (x + 2)(x - y) (x + y)(x - 2) (x - y)(x + 2) · Prove that |x^2x^2-( y-z)^2y z y^ · Factor: (i) x^(3)-2x^(2) ·