Question

what is the ans of this qns​

Answer 1

Answer:

Given ,

$\frac{2^3^0 + 2^2^0 + 2^2^2}{2^3^1 + 2^3^0 - 2^2^9} = \frac{1}{10}$

$LHS = \frac{2^3^0 + 2^2^0 + 2^2^}{2^3^1 + 2^3^0 - 2^2^9}$

        $= \frac{1024+ 1 + 4}{2^9(4 + 2 -1)}$

        $= \frac{1029}{512 * 5}$

        $= \frac{1029}{2560}$

        ≠ $\frac{1}{10}$

        ≠ $RHS$

                  HOPE IT HELPS YOU^_^