Question

1 point
11. The perimeter of a triangle with vertices (O , 4) (0, 0) and (3, 0) is
O 15 units
O 8 units
O 10 units
O 12 units​

Answer 1

Step-by-step explanation:

Using distance formula:

Distance between (0,4) and (0,0) is:

= > √{ (4-0)² + (0-0)² } = √4² = 4

Distance betweem (0,0) and (3,0) is:

= > √{ (0-3)² + (0-0)² } = √3² = 3

Distance betweem (0,4) and (3,0) is:

= > √{ (0-3)² + (0-4)² } = √(3²+4²) = √25 = 5

Perimeter = sum of all sides

Here,

Perimeter = 3 + 4 + 5

Perimeter = 12

Answer 2

Answer:

d) 12 units

Step-by-step explanation:

Assume a triangle ABC having A (0,4), B (0,0) and C (3,0).

Distance between AC = √(x1 + x2)² + (y1 + y2)²

AC = √(3)² + (4)²

AC = √(9 + 16)

AC = √25

AC = 5 units

Distance between BC = √(3)² + (0)²

BC = √9

BC = 3 units

Using Pythagoras theorem,

AB² = AC² - BC²

AB² = 25 - 9

AB² = 16

AB = 4 units

Perimeter of triangle = Sum of all sides

= 5 + 3 + 4

= 12 units