Physics, asked by naiknawareshruti77, 2 days ago

1 point
9) In a transistor amplifier, Ic =
5.5 mA, le = 5.6 mA. The current
amplification factor is
45
O 50
0 55
60

Answers

Answered by rajaswanik

1

Answer:

55

Explanation:

curent gain = output/input

B = ce

ic/ib

5.6 = Ib+5.5

0.1ma

5.5/0.1

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