Question

1
.
PP
5.
11 grams of a gas occupy 5.6 litres of volume at STP. The gas is :-
(1) NO
(2) NO
(3) CO
(4) CO​

Answer 1

Answer:

To find volume of gas at STP

given mass / molar mass = n

n= 11/a ___ (1)

volume/22.4 = n

5.6/22.4 = 11/a

a= 11 × 22.4 / 5.6

= 44 ____(2)

the gas whose molar mass is 44 is the answer

And that gas is carbon dioxide ( CO2 )

Answer 2

co2 is the right answer