Math, asked by ns1308592, 10 months ago

1. PQR is a triangle, right-angled at P. If PQ= 10 cm
and PR = 24 cm, find QR.
2. ABC is a triangle, right-angled at C. If AB = 25
cm and AC = 7 cm, find BC.
3. A 15 m long ladder reached a window 12 m high
from the ground on placing it against a wall at a
distance a. Find the distance of the foot of the
ladder from the wall.​

Answers

Answered by nisha6053
3

Answer:

PQR is a triangle, right-angled at P. If PQ= 10 cm

and PR = 24 cm, find QR.

Step-by-step explanation:

given,

P is a right angle, PQ= 10 cm, PR= 24 cm

therefore QR=

 \sqrt{pq {}^{2} }  +  \sqrt{pr {}^{2} }

 \sqrt{10 {}^{2} }  +  \sqrt{24 {}^{2} }

 \sqrt{100 + 576}

 \sqrt{676}

26

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