Question

1. Prove that angles opposite to equal sides of an isosceles
triangle are equal.​

Answer 1

Answer:

Let's take a triangle ABC

Step-by-step explanation:

AB=BC

AC=AC (common side)

Hence the angle formed between them is also equal

therefore angle ABC = angle ACB

Answer 2

✯✯ QUESTION ✯✯

Prove that angles opposite to equal sides of an isosceles triangle are equal.

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✰✰ ANSWER ✰✰

Consider a ΔABC in which ∠B=∠C

$\:In\:ΔBAD\:and\:ΔCAD\:$

$⇝∠BAD = ∠CAD (By\:construction)$

$⇝AB = AC(Given)$

$⇝AD = AD (Common)$

$<strong>⇝</strong><strong>So</strong>, ΔBAD ≅ ΔCAD (by\:SAS\:Rule.)$

So, ∠ABD = ∠ACD ,since they are corresponding angles of congruent Triangles.

So,

☛$∠B =∠C$

✺HENCE PROVED✺