Question

1
Q.19. A Conductivity cell has
two platinum electrodes of
area 1.2 cm2 and 0.92 cm apart.
Hence the cell constant is *​

Answer 1

Answer:

Explanation:

1.304 cm-1

Answer 2

Step-by-step Explanation:

Given: Area of cross section (a)= 1.2 $cm^2$  and Length between 2 electrodes (L)= 0.92 $cm$

To be found: The Cell constant (k)

Formula used: $K = \frac{L}{a}$

For a particular electrode-conductor set-up, the cell constant is defined as the ratio between the distance between the two electrodes versus the area of cross section of the two electrodes.

So, by using the formula and putting in given values:

$K = \frac{L}{a} \\\\ = \frac{0.92 cm}{1.2 cm^2} \\\\ = 0.767 cm^-1$

Hence, The Cell constant K is 0.767 $cm^-1$