Math, asked by darshanaparida, 9 months ago

1. Question 2.
How many three-digit numbers which are divisible by 7 can be formed using the first three prime numbers (without repetition)?
Pick ONE option
A) 1
B) 2
C) 4
D) 6

Answers

Answered by BrainlyYoda
26

Solution:

First three prime numbers are 2, 3 and 5

We need to form as many three digit numbers we can form from above given three prime numbers.

Number of ways to form three-digit number from three numbers = 3! = 6 ways

There will be 6 three-digit numbers which are as follows :-

235

253

325

523

352

532

Now, we need to check how many numbers are divisible by 7

Divisibility of 7 => We have to double the last digit of the number given and then subtract it from the remaining number. If is it divisible by 7 then whole number will be divisible by 7.

235

Divisibility of 7 =>

Double last digit 5 i.e. 10

Subtract from remaining number = 23 - 10 = 13

13 is not divisible by 7 that means whole number will not be divisible by 7.

253

Divisibility of 7 =>

Double last digit 3 i.e. 6

Subtract from remaining number = 25 - 6 = 19

19 is not divisible by 7 that means whole number will not be divisible by 7.

325

Divisibility of 7 =>

Double last digit 5 i.e. 10

Subtract from remaining number = 32 - 10 = 13

22 is not divisible by 7 that means whole number will not be divisible by 7.

523

Divisibility of 7 =>

Double last digit 3 i.e. 6

Subtract from remaining number = 52 - 6 = 46

46 is not divisible by 7 that means whole number will not be divisible by 7.

352

Divisibility of 7 =>

Double last digit 2 i.e. 4

Subtract from remaining number = 35 - 4 = 31

31 is not divisible by 7 that means whole number will not be divisible by 7.

532

Divisibility of 7 =>

Double last digit 2 i.e. 4

Subtract from remaining number = 53 - 4 = 49

49 is divisible by 7 that means whole number will be divisible by 7.

Only A) 1 i.e. 532 out of all three-digit numbers will be divisible by 7.

Answered by amitnrw
7

Given : three-digit numbers  formed using the first three prime numbers (without repetition)

To find :  how many numbers  which are divisible by 7

Solution:

First three prime numbers are  2  , 3  & 5

6 numbers can be formed  using these 3 digits with out repetition

235  

253

325

352

523

532

235  = 7 * 33 + 4

253 = 7 * 36  + 1

325 = 7 * 46  + 3

352 = 7 * 50 + 2

523 = 7 *74 + 5

532 = 7 * 76

532  is the only  three-digit number  which is  divisible by 7 can be formed using the first three prime numbers(without repetition)

only 1   three-digit number  which is  divisible by 7 can be formed using the first three prime numbers (without repetition)

Option A  is correct

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