1/((root 2)-(1)) evaluate the expression
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1/(√2 -1)
rationalizing it,
[1×(√2 +1)]/[(√2 -1)(√2 +1)]
= (√2 +1)/[(√2)² - (1)²]
=(√2 +1)/1 =(√2 +1)
rationalizing it,
[1×(√2 +1)]/[(√2 -1)(√2 +1)]
= (√2 +1)/[(√2)² - (1)²]
=(√2 +1)/1 =(√2 +1)
Answered by
1
1/(√2 -1)
rationalizing it,
[1×(√2 +1)]/[(√2 -1)(√2 +1)]
= (√2 +1)/[(√2)² - (1)²]
=(√2 +1)/1 =(√2 +1)
rationalizing it,
[1×(√2 +1)]/[(√2 -1)(√2 +1)]
= (√2 +1)/[(√2)² - (1)²]
=(√2 +1)/1 =(√2 +1)
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