Math, asked by checkoutpri9626, 1 year ago

(1/root7+root5)-(1/root5+root3)-(1/root3+root2

Answers

Answered by sahasraramadugu2005
0

=(1/√7+√5 )- (1/√5+√3) -(1/√3+√2)

=(1/√7+√5×√7-√5/√7-√5) - (1/√5+√3×√5-=√3/√5-√3) - (1/√3+√2×√3-√2/√3-√2)

=[√7-√5/(√7)² - (√5)²]-[√5-√3/(√5)² - =(√3)²]-[√3-√2/(√3)² - (√2)²]

=(√7-√5/7-5)-(√5-√3/5-3)-(√3-√2/3-2)

=√7-√5/2 - √5-√3/2 - √3-√2/1

=√7+2√5-√3/2 - √3-√2/1

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