Math, asked by satvinderrana911, 1 month ago

1\root9-root8 is equal to​

Answers

Answered by Bhoomi1116
1

Step-by-step explanation:

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Answered by ajr111
3

Answer:

√9+√8

Step-by-step explanation:

\frac{1}{\sqrt{9}- \sqrt{8} }  = \frac{\sqrt{9} +\sqrt{8} }{(\sqrt{9}- \sqrt{8} )(\sqrt{9} +\sqrt{8} )}  = \frac{\sqrt{9} +\sqrt{8} }{9-8} = \frac{\sqrt{9}+ \sqrt{8} }{1}   = \sqrt{9}+ \sqrt{8}

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