Question

1/s^2(s2+25) find inverse laplace transform
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Answer 1

Answer:

Now the inverse Laplace transform of 2 (s−1) is 2e1 t. Less straightforwardly, the inverse Laplace transform of 1 s2 is t and hence, by the first shift theorem, that of 1 (s−1)2 is te1 t.

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Inverse Laplace Transforms.

Function Laplace transform

1 s1

t 1s2

t^n n!sn+1

eat 1s−a

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Answer 2

Answer:

Step-by-step explanation: