Question

1. Sample A (blue) + heat Residue B (black) +Gas C(acidic) + Gas D [2] (reddish brown) ( neutral) Identify A, B, C and D.

Answer 1

On heating lead (II) nitrate gives a brown gas " A". The gas " A" on cooling changes to colourless solid "B" . Solid B on heating with NO changes to a blue solid 'C . Identify ' A', 'B' and' C and also write reactions involved and draw the structures of 'B' and 'C' .

Answer 2

A: lead nitrate

B: lead oxide

C: no gas, if neutral it had been oxygen

D: nitrogen dioxide

Explanation:

• The sample which is given above denotes the heating of lead nitrate to liberate a black substance which is lead oxide which is the residue.

• A neutral gas oxygen is liberated along with a reddish brown gas which is nitrogen dioxide ,in this example in lead nitrate can be proved by the brown ring test which is given by most of the nitrates

containing substances.

2Pb(NO3)2 ----------> 2PbO +2 NO2 + 3O2

To know more,

mention the nature and color of the following salts- zinc carbonate .

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