Math, asked by freddyturtle19, 10 months ago

1+sec^2 theta sin^2 theta=sec^2 theta

Answers

Answered by jp786111
1

Answer:

1+sec^2 theta sin^2 theta=sec^2 theta

LHS

1+sec^2 theta sin^2 theta

tan^2 theta 1-cos^2 theta

sin^2 theta/cos^2 theta 1-cos^2 theta

sin^2 theta cos^2 theta-cos^2 theta

sin^2 theta

1/cos^2 theta

sec^2 theta

LHS=RHS

ANSWER:

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