Question

1- sec^4 theta + tan^4 theta/1- sec^2 theta​

Answer 1

Step-by-step explanation:

Here,

1-sec⁴A+tan⁴A/(1-sec²A)

=(1-sec⁴A)-(sec²A-1)²/(sec²A-1)

=(1-sec⁴A)-(sec²A-1)

=1-sec⁴A-sec²A+1

= -(sec⁴A+sec²A-2)

= -(sec⁴A+2sec²A-sec²A-2)

= -{sec²A(sec²A+2)-1(sec²A+2)}

= -(sec²A+2)(sec²A-1)

= -tan²A(sec²A+2)

Answer 2

Answer:

The answer is :

2

Hope i have answered ur question