Question

1/sec A-1 + 1/sec A + 1 = 2 cosec A cotA​

Answer 1

Answer:

$\frac{1}{sec a + 1} + \frac{1}{seca - 1} = \frac{seca + 1 + seca - 1}{(seca + 1)(seca - 1)} = \frac{2seca }{ {sec}^{2}a - 1 } = \frac{2seca}{ {tan}^{2}a } = 2coseca.cota$

Answer 2

Answer:

Proved ! ! !

Step-by-step explanation:

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