Math, asked by sam1344, 4 months ago

1+sec a /sec a=sin²a/1-cos a​

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Answered by jaimadhav2005
1

Answer:

Here is your answer thanks

Step-by-step explanation:

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Answered by riteshaleti161
0

Step-by-step explanation:

1+sec a/sec a=sin^2/1-cos a

(1+1/cos a)/1/cos a= 1-cos^2 a/1-cos a

cos a+1/cos a/1/cos a=(1+cos a)(1-cos a)/(1- cos a)

cos a+1=cos a+1

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