Math, asked by yashpthk, 1 year ago

1/sec A +tan A
= sec A-tan A

Answers

Answered by lakshitamiglani

1

Step-by-step explanation:

1/secA+tanA×secA-tanA/secA-tanA= secA-tanA/sec^2A-tan^2A

secA-tanA/1

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