Math, asked by sanjeev105, 1 year ago

1/sec A + tanA=sec A-tanA

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Answered by sanjanashetty30

hope this helps you...

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Answered by YadavShashi

$\frac{1}{sec \: a \: + tan \: a \: } = \frac{}{} sec \: a \: - tan \: a \: \\ 1 = (sec \: a \: - tan \: a \: )(sec \: a \: + tan \: a \: ) \\ 1 = sec {}^{2} a \: - tan \: {}^{2} a$

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