Question

1/sec A + tanA=sec A-tanA

Answer 1

hope this helps you...

Answer 2

$\frac{1}{sec \: a \: + tan \: a \: } = \frac{}{} sec \: a \: - tan \: a \: \\ 1 = (sec \: a \: - tan \: a \: )(sec \: a \: + tan \: a \: ) \\ 1 = sec {}^{2} a \: - tan \: {}^{2} a$