1 + sec a upon sec a = 2 sin square a upon 1 minus cos a
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the RHS is sin^2 A/1 - cos A = sin^2A - cos A which is not the same as the LHS. I suppose you mean the relation to be. (1 + sec A)/ sec A ...
the RHS is sin^2 A/1 - cos A = sin^2A - cos A which is not the same as the LHS. I suppose you mean the relation to be. (1 + sec A)/ sec A ...3 votes
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