Question

1 + sec a upon sec a = 2 sin square a upon 1 minus cos a

Answer 1

Answer:

the RHS is sin^2 A/1 - cos A = sin^2A - cos A which is not the same as the LHS. I suppose you mean the relation to be. (1 + sec A)/ sec A ...

the RHS is sin^2 A/1 - cos A = sin^2A - cos A which is not the same as the LHS. I suppose you mean the relation to be. (1 + sec A)/ sec A ...3 votes