Question

Seven white balls and three black balls are randomly arranged i. A row

Answer 1

Answer:

Placing 7 white balls in a row leaves 8 gaps. The 3 black balls can be placed in 8 gaps in ways. So, the total number of ways of arranging white and black balls such that no two black balls are adjacent = 56*3!* ... Actual number of arrangements possible with 7 white and 3 black balls = (7+3)!