Question

1-sec +tan ÷1+ sec 0-tan = sec +tan +1 sec+tan +1​

Answer 1

Answer:

I am not sure this is true answer

Step-by-step explanation:

this answer is brainly and difficult

Answer 2

Answer:

2 tan A

Step-by-step explanation:

LHS=(secA+tanA−1)(secA−tanA+1)

=(

cosA

1

+

cosA

sinA

−1)(

cosA

1

−

cosA

sinA

+1)

=(

cosA

1+sinA−cosA

)(

cosA

1−sinA+cosA

)

=

cos

2

A

1−sinA+cosA+sinA−sin

2

A+sinAcosA−cosA+sinAcosA−cos

2

A

=

cos

2

A

2sinAcosA

=2tanA