Question

1 / secA +1 + 1/ secA-1 = 2 cosecAcotA

Answer 1

Hiii

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1/secA-1 + 1/secA+1=2cosecA.cotA

LHS:

=secA+1+secA-1/sec²A-1

=2secA/tan*A

=2/cosA÷sin*A/cos*A

=2cosA (cos*A/sin*A)

=2×(1/sinA)×(cosA/sinA)

=2cosecA.cotA=RHS

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Hope it will help u................