Math, asked by mani94665chahal, 4 months ago

1+secA/secA=sin^2A/1-cosA

Answers

Answered by sangamrani112

1

Step-by-step explanation:

To prove =1+secA= sec12A

secA. 1-cosA

1

LHS. 1+secA= 1+cosA

secA. 1

= cosA

= cosA+1

cosA

1

=cosA+1 ×cosA

cosA. 1

1+cosA

=1+cosA× 1- cosA

1- cosA

=(1)2 - (cosA)2

1. - cosA

=1-cos2A

1-cosA

=sin 2A

1-cosA

=RHS

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