Question

The intensity of a radio signal is 0.120 W/m² at distance of 16.0m from a small transmitter. What is the intensity of the signal 4.00m from the transmitter?​

Answer 1

Answer:

hope it will help you...........

Answer 2

Answer: The intensity of the signal at $4m$ is $1.92 W/m^{2}$.

Explanation:

The square of the distance between the source and the observer determines how intense the light is for the observer. This demonstrates that the intensity of light is proportional to a value multiplied by $1 / d^{2}$ as the distance to a light source rises.

Now the intensity  at  $16m$ distance is given $0.120 W/m^{2}$, we have to calculate intensity at $4m$.

As $I$ ∝ $1/ d^{2}$

$\frac{I_{1} }{I_{2} }= \frac{d^{2} _{2} }{d^{2} _{1}}$

$I_{1} = 0.12 W/m^{2}$, $d_{1}= 16m$, $I_{2} = ?$, $d_{2} = 4m$

Putting the values to calculate $I_{2}$

$\frac{0.12 W/m^{2} }{I_{2} }= \frac{4^{2} }{16^{2} }$

$I_{2} = \frac{0.12 W/m^{2} * 256 }{16} = 1.92 W/m^{2}$

Therefore the intensity of the signal at $4m$ is $1.92 W/m^{2}$.

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