Question

1+SecA÷SecA=Sin square A÷1-cosA

Answer 1

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Answer 2

Answer:

Step-by-step explanation:

1+secA/secA=sinsquareA/1-cosA

1/secA + secA/secA (seperating lcm)

CosA+1 =lhs ( 1/secA=cosA) and

(secA/secA=1)

Rhs = sin square/1-cosA

1-cos square A/1-cosA

(1+cosA)(1-cosA)/1-cosA

1+cosA=Rhs=lhs