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here, tan A= 1
=>tan A = tan 45°
=> A= 45°
tanB= √3
=>tan B = tan 60°
=>B = 60°
(i) cosA cos B -sinA sinB
= cos 45° cos60° - sin45° sin60°
=1/√2 * 1/2 - 1/√2 * √3/2
=1/2√2 - √3/2√2
=(1- √3)/2√2
(ii) sinA cosB + cosA sin B
=sin 45 cos60 + cos 45 sin 60
=1/√2* 1/2 + 1/√2* √3/2
= 1/2√2 + √3/2√2
=(1+√3)/2√2
that's your ans .........
=>tan A = tan 45°
=> A= 45°
tanB= √3
=>tan B = tan 60°
=>B = 60°
(i) cosA cos B -sinA sinB
= cos 45° cos60° - sin45° sin60°
=1/√2 * 1/2 - 1/√2 * √3/2
=1/2√2 - √3/2√2
=(1- √3)/2√2
(ii) sinA cosB + cosA sin B
=sin 45 cos60 + cos 45 sin 60
=1/√2* 1/2 + 1/√2* √3/2
= 1/2√2 + √3/2√2
=(1+√3)/2√2
that's your ans .........
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