(1+secA)/secA=(sin2A)/(1-cosA)
Answers
Answered by
0
Answer:
by LHS
1+secA/secA
=1+1/cosA/1/cosA
=1+cosA/1
rationalising the numerator
=1+cosA/1×1-cosA/1-cosA
=1-cos^2A/1-cosA
=sin^2A/1-cosA=RHS hence proved
Similar questions