Math, asked by asmitsharma731, 6 hours ago

(1+secA)/secA=(sin2A)/(1-cosA)

Answers

Answered by datars211gmilcom

0

Answer:

by LHS

1+secA/secA

=1+1/cosA/1/cosA

=1+cosA/1

rationalising the numerator

=1+cosA/1×1-cosA/1-cosA

=1-cos^2A/1-cosA

=sin^2A/1-cosA=RHS hence proved

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