(1+secA+tanA)(1-cosecA+cotA)=2 prove that
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when you convert them into sin and cos and take l.c.m. you will get the denominator sina in one bracket and cos a on another bracket and the numerator will be sina +cosa +1 in one bracket and sina +cos a-1 in another bracket when you multiply them you will get in the numerator (sina+cosa)^2 - 1
in the denominator you will get sinacosa
when you solve the numerator the one will be canceled and the remaining would be 2sinacosa and cutting den. and num. you will get the answer
in the denominator you will get sinacosa
when you solve the numerator the one will be canceled and the remaining would be 2sinacosa and cutting den. and num. you will get the answer
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