Math, asked by sanghamitapattnaik56, 6 days ago

1+(secA-tanA)²/secA(cosecA-cotA)=2tanA​

Answers

Answered by sheejamohan79
0

2 tan A

= (sec^ A-tan^A)+(sec A - tan A^) / cosecA(sec A- tanA)

= (sec A + tan A)+(sec A - tan A) / cosecA

= 2sec A / cosec A

= 2 cos A / 1/sin A

= 2 tan A

Similar questions