Question

а In a triangle ABC , if A + B = 85° and B + C = 160° , find angle A , B and C ?​

Answer 1

Answer:

Angle A , B and C are 20 , 65 and 95 respectively.

Step-by-step explanation:

In a triangle ABC ,

                      $A + B =$ $85^0$

and                 $B + C = 160^0$

so    

            $A+B+B+C=85+160\\ \\ B+(A+B+C)=245 ^0$

We know that,

                   $(A+B+C)=180^0\\ \\ B+180^0=245^0\\ \\ B=245^0-180^0=65^0$    

Thus,  

         $A + B = 85^0\\ \\ A=85^0-65^0=20^0$

Again,

      $B+C=160^0\\ \\ C=160^0-B=160^0-65=95^0$