1/secA+tanA = secA - tanA
Answers
Answered by
2
Answer:
Step-by-step explanation:
Attachments:

ana03nya:
impressive! thank you!
Answered by
3
1/secA+tanA×secA-tanA
=secA-tanA/secA×secA-tanA×tanA
=secA-tanA ... (sec squareA reduced by tan square A equals to 1)
Similar questions