Math, asked by ana03nya, 11 months ago

1/secA+tanA = secA - tanA

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Answered by brunoconti

2

Answer:

Step-by-step explanation:

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ana03nya: impressive! thank you!

Answered by suraj6454

3

1/secA+tanA×secA-tanA

=secA-tanA/secA×secA-tanA×tanA

=secA-tanA ... (sec squareA reduced by tan square A equals to 1)

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