Question

A rectangular tank measures 4m long, 2m wide, and 4.8m high. Initially it is half filled with water. Find the depth if water in the tank after 4000litres mire of water are added to it

Answer 1

Solution :-

Given :

A cuboidal tank measures 4m long, 2m wide, and 4.8m high.

Volume of cuboid = lbh cu. units

= (4 × 2 × 4.8) m³

= 38.4 m³

We know that,

1 m³ = 1000 l

∴ 38.4 m³ = (1000 × 38.4) l = 38400 l

Given : Initially it is half filled with water.

Half of the tank = 38400/2 = 19200 l

Volume of water after the 4000 litres more of water are added = (19200 + 4000) = 23200 l

1000 l = 1 m³

23200 l = (23200/1000) m³ = 23.2 m³

Find the depth of water in the tank :-

=> Volume of water in the tank = lbh cu. units

=> 23.2 = (4 × 2 × h)

=> h = 23.2/8 = 2.9

Hence,

The depth of water in the tank = 2.9 m

Answer 2

Answer:

Step-by-step explanation:

Given that,

lenght of tank=4m

Width of tank =2m

Initally height=4.8m

Now?

Initally volume =(4×2×4.8)m^3

= 38.4m^3

Now,

4000 l of water is pumped into the tank

So,

Total volume of tank=38.4m^3+4 m^3

=42.4 m^3

Now,

The volume tank =4m×2m×h=42.4m^3

=8m^2h=42.4m^3

H=42.4/8m

5.3m