Question

1

Secondary SchoolMath8 points

A women has a certain number of mangoes of which 13% are rotten.She gives 75% of the remainder in charity and then has 261 left.How many had she at first?


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Answer 1

13+75=88%

so left mangoes are 12%

so x*12/100=261

x=261*100/12

x=2175 ( the total number of mangoes )

Answer 2

Answer:

2175 Mangoes

Step-by-step explanation:

total mangoes= 100%

rotten=100%-13%=87%

remainder=87%-75%(for charity)=12%

12% is her remainder which = 261 mangoes

orignal          remainder

100                   12

x                        261

now cross multiply

100×261=26100

12×x=12x

26100=12x     now divide 12x by 12 to remain with x and also do the same for 26100...

26100÷12=2175 mangoes