Math, asked by manyaraswant69, 6 months ago

1+sectheta-tantheta/1+sectheta±tantheta​

Answers

Answered by sandy1816
0

 \frac{1 + sec \theta - tan \theta}{1 + sec \theta + tan \theta}  \\  \\  =  \frac{( {sec}^{2}  \theta -  {tan}^{2} \theta) + (sec \theta  - tan \theta) }{1 + sec \theta + tan \theta}  \\  \\  =  \frac{(sec \theta - tan \theta)(sec \theta  + tan \theta + 1)}{1 + sec \theta + tan \theta}  \\  \\  = sec \theta - tan \theta \\  \\  =  \frac{1 - sin \theta}{cos \theta}

Hopes it helps

Similar questions