Question

1/secx-tanx - 1/cosx = 1/cosx - 1/secx+tanx

Answer 1

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$\huge \boxed{ \mathbb{ANSWER:}}$

$<H3> See the attachment for your answer.$

$\large \boxed{ \mathbb{TRIGONOMETRY.}}$

$\huge \bf \underline{ \mathbb{LHS = RHS.}}$

✔✔Hence, it is proved ✅✅.

$\huge \boxed{ \mathbb{THANKS}}$

#BeBrainly.

Answer 2

here is your answer OK dude


LHS :- ( 1/secX - tanX) - 1/cosX

= [ 1(secX + tanX) / secX - tanX (secX +tanX)] - secX

= [ secX + tanX /sec2X - tan2X] - secX

= secX +tanX - secX

=tanX

RHS :- 1/cosX - 1/secX+tanX

=secX -[ 1(secX - tanX)/secX+tanX(secX-tanX)]

=secX - ( secX - tanX / sec2X - tan2X)

=secX - secX + tanX

= tanX

So, LHS = RHS. hence proved.