p^2-17p-38 factorise
Answers
Answered by
83
Hey mate,
p²-17p-38=0
p²-19p+2p-38=0
p(p-19)+2(p-19)=0
(p-19)(p+2)=0
=>p= 19 or p= -2 ANSWER...
HOPE IT HELPS:-))
p²-17p-38=0
p²-19p+2p-38=0
p(p-19)+2(p-19)=0
(p-19)(p+2)=0
=>p= 19 or p= -2 ANSWER...
HOPE IT HELPS:-))
Answered by
39
sum = -17
product= -38×1= -38
the numbers are -19 and 2
p^2 +2p-19p-38
p(p+2)-19(p+2)
(p+2)(p-19)
product= -38×1= -38
the numbers are -19 and 2
p^2 +2p-19p-38
p(p+2)-19(p+2)
(p+2)(p-19)
aryan2599:
thnx
Similar questions